9.1x^2+4.1x-3.4=0

Solution for 9.1x^2+4.1x-3.4=0 equation:

9.1x^2+4.1x-3.4=0

a = 9.1; b = 4.1; c = -3.4;
Δ = b2-4ac
Δ = 4.12-4·9.1·(-3.4)
Δ = 140.57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.1)-\sqrt{140.57}}{2*9.1}=\frac{-4.1-\sqrt{140.57}}{18.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.1)+\sqrt{140.57}}{2*9.1}=\frac{-4.1+\sqrt{140.57}}{18.2}
$